2x^2+14x+49=490

Solution for 2x^2+14x+49=490 equation:

2x^2+14x+49=490

We move all terms to the left:

2x^2+14x+49-(490)=0

We add all the numbers together, and all the variables

2x^2+14x-441=0

a = 2; b = 14; c = -441;
Δ = b2-4ac
Δ = 142-4·2·(-441)
Δ = 3724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3724}=\sqrt{196*19}=\sqrt{196}*\sqrt{19}=14\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14\sqrt{19}}{2*2}=\frac{-14-14\sqrt{19}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14\sqrt{19}}{2*2}=\frac{-14+14\sqrt{19}}{4}
$